Difference between revisions of "Fusion Propulsion"
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Fusion Propulsion | Fusion Propulsion | ||
| + | {| class="wikitable" | ||
| + | | colspan="16" rowspan="1" |Table 1 - Significant fusion reactions | ||
| + | |- | ||
| + | | colspan="4" rowspan="1" |Reaction | ||
| + | |→ | ||
| + | | colspan="9" rowspan="1" |Products | ||
| + | |Total | ||
| + | Energy release | ||
| + | |Atomic mass of products | ||
| + | |- | ||
| + | | | ||
| + | | colspan="3" rowspan="1" | | ||
| + | | | ||
| + | | | ||
| + | |ratio | ||
| + | |MeV/ fusion | ||
| + | | | ||
| + | | | ||
| + | |MeV/ fusion | ||
| + | | | ||
| + | | | ||
| + | |MeV/ fusion | ||
| + | |GJ/kg | ||
| + | |N | ||
| + | |- | ||
| + | |1 | ||
| + | |D | ||
| + | | + | ||
| + | |T | ||
| + | |→ | ||
| + | |He4 | ||
| + | |100% | ||
| + | |3.49 | ||
| + | | + | ||
| + | |n0 | ||
| + | |14.1 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |340 000 | ||
| + | |5 | ||
| + | |- | ||
| + | |2a | ||
| + | |D | ||
| + | | + | ||
| + | |D | ||
| + | |→ | ||
| + | |He3 | ||
| + | |50% | ||
| + | |0.82 | ||
| + | | + | ||
| + | |n0 | ||
| + | |2.45 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |79 000 | ||
| + | |4 | ||
| + | |- | ||
| + | |2b | ||
| + | | | ||
| + | | + | ||
| + | |D | ||
| + | |→ | ||
| + | |T | ||
| + | |50% | ||
| + | |01.01 | ||
| + | | + | ||
| + | |p+ | ||
| + | |03.02 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |97 000 | ||
| + | |4 | ||
| + | |- | ||
| + | |3 | ||
| + | |D | ||
| + | | + | ||
| + | |He3 | ||
| + | |→ | ||
| + | |He4 | ||
| + | |100% | ||
| + | |3.6 | ||
| + | | + | ||
| + | |p+ | ||
| + | |14.7 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |353 000 | ||
| + | |5 | ||
| + | |- | ||
| + | |4 | ||
| + | |T | ||
| + | | + | ||
| + | |T | ||
| + | |→ | ||
| + | |He4 | ||
| + | |100% | ||
| + | | | ||
| + | | + | ||
| + | |2x n0 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |11.3 | ||
| + | |182 000 | ||
| + | |6 | ||
| + | |- | ||
| + | |5 | ||
| + | |He3 | ||
| + | | + | ||
| + | |He3 | ||
| + | |→ | ||
| + | |He4 | ||
| + | |100% | ||
| + | | | ||
| + | | + | ||
| + | |2x p+ | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |12.9 | ||
| + | |207 000 | ||
| + | |6 | ||
| + | |- | ||
| + | |6a | ||
| + | |He3 | ||
| + | | + | ||
| + | |T | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |n+ | ||
| + | |12.1 | ||
| + | | + | ||
| + | |p+ | ||
| + | | | ||
| + | |195 000 | ||
| + | |6 | ||
| + | |- | ||
| + | |6b | ||
| + | | | ||
| + | | + | ||
| + | |T | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | |4.8 | ||
| + | | + | ||
| + | |D | ||
| + | |9.5 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |230 000 | ||
| + | |6 | ||
| + | |- | ||
| + | |6c | ||
| + | | | ||
| + | | + | ||
| + | |T | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | |0.5 | ||
| + | | + | ||
| + | |n0 | ||
| + | |1.9 | ||
| + | | + | ||
| + | |p+ | ||
| + | |11.9 | ||
| + | |230 000 | ||
| + | |6 | ||
| + | |- | ||
| + | |7a | ||
| + | |D | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |He4 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |22.4 | ||
| + | |270 000 | ||
| + | |8 | ||
| + | |- | ||
| + | |7b | ||
| + | | | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |He3 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |He4 | ||
| + | | | ||
| + | | + | ||
| + | |n0 | ||
| + | |2.56 | ||
| + | |31 000 | ||
| + | |8 | ||
| + | |- | ||
| + | |7c | ||
| + | | | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |Li7 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |p+ | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |5.0 | ||
| + | |60 000 | ||
| + | |8 | ||
| + | |- | ||
| + | |7d | ||
| + | | | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |Be7 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |n0 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |3.4 | ||
| + | |41 000 | ||
| + | |8 | ||
| + | |- | ||
| + | |8 | ||
| + | |p+ | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | |1.7 | ||
| + | | + | ||
| + | |He3 | ||
| + | |2.3 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |55 000 | ||
| + | |7 | ||
| + | |- | ||
| + | |9 | ||
| + | |n | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |T | ||
| + | |2.3 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |7 | ||
| + | |- | ||
| + | |10 | ||
| + | |He3 | ||
| + | | + | ||
| + | |Li6 | ||
| + | |→ | ||
| + | |He4 | ||
| + | | | ||
| + | | | ||
| + | | + | ||
| + | |He4 | ||
| + | | | ||
| + | | + | ||
| + | |p+ | ||
| + | |16.9 | ||
| + | |181 000 | ||
| + | |9 | ||
| + | |- | ||
| + | |11 | ||
| + | |p+ | ||
| + | | + | ||
| + | |B11 | ||
| + | |→ | ||
| + | |3x He4 | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | | | ||
| + | |8.7 | ||
| + | |70 000 | ||
| + | |12 | ||
| + | |- | ||
| + | |12 | ||
| + | |6D | ||
| + | | | ||
| + | | | ||
| + | |→ | ||
| + | |2x He4 | ||
| + | | | ||
| + | |8.92 | ||
| + | | + | ||
| + | |2n0 | ||
| + | |16.55 | ||
| + | | + | ||
| + | |2p+ | ||
| + | |17.72 | ||
| + | |348 000 | ||
| + | |12 | ||
| + | |- | ||
| + | | colspan="16" rowspan="1" |Total energy release = sum of energies (MeV) x 1.6e-19 J/eV / mass of reaction products | ||
| + | Mass of reaction products = N x atomic mass unit (1.66e-27 kg) | ||
| + | In a fusion reaction, the portion of the fuel that actually reacts is called the burnup fraction. As a first order of magnitude evaluation, we can establish that a fusion drive with a burnup fraction of 10%, using 1 kg of deuterium+he3 per second will produce 353 000 GJ/kg x 1kg/s x 0,1 = 35 300 GW of power (Line 4, table 1). | ||
| + | To find the thrust from the fusion reaction, F=ṁ*2Pt*ηn . For an efficiency (ηn) of 80%, the force is 5 600 KN or 576 tonnes. | ||
| + | To find the exhaust velocity Ve=F/ṁ= 56 500 000 N / 1 kg/s = 5 650 000 m/s | ||
| + | |} | ||
[[Category:Propulsion]] | [[Category:Propulsion]] | ||
Revision as of 05:52, 2 September 2021
Fusion Propulsion
| Table 1 - Significant fusion reactions | |||||||||||||||
| Reaction | → | Products | Total
Energy release |
Atomic mass of products | |||||||||||
| ratio | MeV/ fusion | MeV/ fusion | MeV/ fusion | GJ/kg | N | ||||||||||
| 1 | D | + | T | → | He4 | 100% | 3.49 | + | n0 | 14.1 | 340 000 | 5 | |||
| 2a | D | + | D | → | He3 | 50% | 0.82 | + | n0 | 2.45 | 79 000 | 4 | |||
| 2b | + | D | → | T | 50% | 01.01 | + | p+ | 03.02 | 97 000 | 4 | ||||
| 3 | D | + | He3 | → | He4 | 100% | 3.6 | + | p+ | 14.7 | 353 000 | 5 | |||
| 4 | T | + | T | → | He4 | 100% | + | 2x n0 | 11.3 | 182 000 | 6 | ||||
| 5 | He3 | + | He3 | → | He4 | 100% | + | 2x p+ | 12.9 | 207 000 | 6 | ||||
| 6a | He3 | + | T | → | He4 | + | n+ | 12.1 | + | p+ | 195 000 | 6 | |||
| 6b | + | T | → | He4 | 4.8 | + | D | 9.5 | 230 000 | 6 | |||||
| 6c | + | T | → | He4 | 0.5 | + | n0 | 1.9 | + | p+ | 11.9 | 230 000 | 6 | ||
| 7a | D | + | Li6 | → | He4 | + | He4 | 22.4 | 270 000 | 8 | |||||
| 7b | + | Li6 | → | He3 | + | He4 | + | n0 | 2.56 | 31 000 | 8 | ||||
| 7c | + | Li6 | → | Li7 | + | p+ | 5.0 | 60 000 | 8 | ||||||
| 7d | + | Li6 | → | Be7 | + | n0 | 3.4 | 41 000 | 8 | ||||||
| 8 | p+ | + | Li6 | → | He4 | 1.7 | + | He3 | 2.3 | 55 000 | 7 | ||||
| 9 | n | + | Li6 | → | He4 | + | T | 2.3 | 7 | ||||||
| 10 | He3 | + | Li6 | → | He4 | + | He4 | + | p+ | 16.9 | 181 000 | 9 | |||
| 11 | p+ | + | B11 | → | 3x He4 | 8.7 | 70 000 | 12 | |||||||
| 12 | 6D | → | 2x He4 | 8.92 | + | 2n0 | 16.55 | + | 2p+ | 17.72 | 348 000 | 12 | |||
| Total energy release = sum of energies (MeV) x 1.6e-19 J/eV / mass of reaction products
Mass of reaction products = N x atomic mass unit (1.66e-27 kg) In a fusion reaction, the portion of the fuel that actually reacts is called the burnup fraction. As a first order of magnitude evaluation, we can establish that a fusion drive with a burnup fraction of 10%, using 1 kg of deuterium+he3 per second will produce 353 000 GJ/kg x 1kg/s x 0,1 = 35 300 GW of power (Line 4, table 1). To find the thrust from the fusion reaction, F=ṁ*2Pt*ηn . For an efficiency (ηn) of 80%, the force is 5 600 KN or 576 tonnes. To find the exhaust velocity Ve=F/ṁ= 56 500 000 N / 1 kg/s = 5 650 000 m/s | |||||||||||||||





